Thanks Gary! That makes sense.



I think this should be P=EI=RI^2 (because E=IR)



I agree, that's all I would care about after buying the system. But when shopping for a system or deciding what system to use where it helps to understand how different systems have been rated.

Thanks
Shiral

I think this should be P=EI=RI^2 (because E=IR)

Yes, you are correct. I neglected to type the final segment of the formula.

Must be gettin' old,

Gary

I guess that value results by the stereo effect. -> 2 times 500 watts = 1000 Watts <-
In this case there should be a 2nd fuse somewhere else inside the case.
Imho RMS is a non-related term in electrical engineering. I've only heard about it in combination with master recording (this means tone engineering).

Otherwise the inner circuit for example with 12 volts and 1.5 amps will supply only 18 watts. The same fuse in AC circuit will supply 230 volts x 1.5 amps = 345 watts.
Now calculate 345 watts x SQR(2) to get peak-to-peak power of 487.9 watts!
If you'd round up this value then you'll get the 500 watts which Jarda has written.

The last remaining point I'm thinking about is the manual. Some manufacturers do really write nonsens!!!

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Greetings from Frankfurt (Germany), Sheriff

[This message has been edited by Sheriff (edited 03-09-2005).]